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More importantly, the full moon occupies 0.00077% of our sky, and is moving at 1.022 km/s around the earth. Suffice to say, if you land on the moon, you’ve done something incredible.
The sun is 1.4 million kilometres in diameter, and it is surprisingly hard to throw something into it.
The more important question is how much of our night sky the moon takes up, and the answer is only 0.5 degrees.
How much is that in hamburgers? Sorry I only understand freedom units
Degrees are the freedom unit!
Then you remember that he’s in a 2’407’100 km void.
Ok. What country uses apostrophes instead of commas, or periods? I had thought that India’s messed up comma system was the most irritating notation possible. I had never seen this notation.
This gave me flashbacks to being a new Kerbal Space Program player.
Someday I’ll rescue Jeb from his awkward Solar orbit.
There is a one button solution to lost Kerbalnauts…
True
You could easily fuck it up more. Like, shoot in the opposite direction, or shoot for the sun. Hell, you could just blow the rocket up altogether. Guys, it’s so easy to fuck it up waaayyy more.
Counterpoint:
Orbital semimajor axis of the moon (basically the orbit radius): 384400 km
Subtract earth’s radius: becomes 378000 km above earth’s surface at mean sea level.
Moon radius: 1737.4 km
tan-1(1737.4 / 378000) = 0.26 degrees
Conclusion: at best, assuming the moon is directly overhead and any glancing contact is a success, you can deviate maximally 0.26 degrees from a dead centre hit to hit the moon.
Good luck with that.
Thank you for doing the math on that.
