We’ve known about coronaviruses since the 1960s

So, shooting into a RAM buffer as soon as the shutter is half-pressed, or as soon as focus is locked? Also, how does the lens play a role? The shutter is inside the camera and probably does not engage in fast burst mode anyway.

How many shots per second is that?

Reverse image search says The Triplets of Belleville

Taking off with wet feathers and a fish does take effort though

Knowing the author’s nationality and previous cultural references, I think she’s inspired by Slavic Rusalka myths. Better read up on that archetype before considering a relationship…

Well, it’s a high-speed 3-lane road that would fit 5 parked cars curb to curb so Rettungsgasse is where the space goes. Most other roads can barely yield 1 lane but emergency drivers are skilled and European fire trucks are not 1.5 lanes wide; still better to use a narrow free lane between 2 stationary ones rather than one of 2 crawling ones

This program in 35 kB of LISP-like code beat GPT 3.5 a Turing test, and some people would keep using it despite having seen the code. But I think parasocial relationships with machines date back to early cogs and pulleys…

That’s where the calculus comes in, otherwise it’s a basic Pythagorean theorem. I’ve compiled a list of possible latitudes (with questionable assumptions), knock yourself out

About “самиздат”

Except now the walking speed of 1 m/s (3.6 km/h) and running speed of 5 m/s (18 km/h) are realistic

Instructions unclear, let’s assume he started 1,312,593,975 feet further back (see my other comment)

CASIO calculators say 1, and I think it’s more intuitive with “÷2π” being equivalent to “÷(2×π)” rather than “÷2×π”. It took me a while to figure out why my results were almost but not quite one order of magnitude wrong after I was forced to switch to TI. Obviously nobody in high school or uni wrote ÷ (or Czech :) on paper, it was all fractions, but even on “natural mode” calculators I’d use the ÷ key for simple denominators to save vertical space.

You actually only need to know the latitude for that… except the local terrain will play a larger role anyway, unless they started very close to a pole and follow rhumb lines (in this case ♂︎ a meridian and ♀︎ a circle of latitude) as opposed to great circles, so better just ask for full coordinates.

What? The teacher does not want to talk about it? Let’s find out anyway, to the best of my abilities. For now, we’ll be assuming Earth is a fully walkable ellipsoid.

We don’t have many data points in the question so let’s extrapolate their movement into the past. There is the hint that they met 8 years earlier at the same spot, during which he’d have gone 1 262 304 000 ft or 384 750.2592 km, completing 9.617 polar circumferences of the Earth (40 007.863 km each).

Huh, that’s not a whole number. In some languages, “eight long years” might mean “a little over 8 years” so let’s assume he finished exactly 10 polar circumnavigations, which took 8 years and about 116 days. Her walked distance over that time is 5x smaller, 2 polar circumnavigations’ worth or 80 015.726 km. This is only exactly 2 great circles (ellipses, really) if they are polar, but we know that it’s impossible to go due east from either pole. Therefore, we’ll use the other option you pointed out, of her having gone at a constant bearing of 090, her path being a circle of latitude (aka a “parallel”). To end up in the same spot, she must have not-quite-circumnavigated-but-enough-for-Phileas-Fogg the Earth (aka crossed every meridian but not the equator) an integer number of times. After a simple conversion, we can construct a table of the options.

To calcuate latitude from circle-of-latitude circumference (colc), we’ll be using geodetic ↔ ECEF conversion equations (except those with the perverse prime vertical radius of curvature 𝑁 of course) and their notation (simplified with 𝑦 = 0, 𝜆 = 0, ℎ = 0 to ignore longitude and elevation) with values of the WGS-84 ellipsoid. The relationship we’re seeking is between colc/2𝛑 = 𝑝, circle-of-latitude radius, which is at zero longitude equal to ECEF 𝑋, and 𝜙 (latitude). See also Wikipedia on Earth radius by location but remember to skip anything with 𝑁, we’re not doing that.

The geocentric radius (𝑅) is related to 𝜙 (latitude) like this but we only need the distance to axis of rotation 𝑝.

(𝑍/𝑝)(cot 𝜙) = (1 − 𝑒²) → (𝑏²/𝑎²)(𝑍/𝑝) = 1/(cot 𝜙) = tan 𝜙 → 𝜙 = atan((𝑏²/𝑎²)(𝑍/𝑝))
(using 𝑒² = 1 −  𝑏²/𝑎²)

Since sin² 𝛂 = 1 − cos² 𝛂 and we can normalize 𝑍 and 𝑝 to the unit circle with ellipsoid radii 𝑏 and 𝑎 respectively:
𝑍²/𝑏² = (𝑍/𝑏)² = 1 − (𝑝/𝑎)² = 1 − 𝑝²/𝑎², therefore 𝑍 = √(𝑏²(1 − 𝑝²/𝑎²)).

All in all, 𝑝 → 𝜙 conversion is:
𝜙 = atan((𝑏²/𝑎²)(√(𝑏²(1 − 𝑝²/𝑎²))/𝑝))

(Presumably, this could be simpified further but I can just put this into a calculator so idc)
Per WGS-84:
𝑎 = 6378.137 km
𝑏 = 6356.752 km

Here are the results. Finding appropriate meeting locations at some of the 25+ possible latitudes on either hemisphere is left as an exercise to the reader. Also note that “rainy days” don’t occur in some places, which is why I didn’t bother adding more rows after I got within 500 km of the pole.

Rows where the number of not-quite-circumnavigations is divisible by 2, 5, or 10 are especially interesting because then the couple would meet 3, 6 and 11 times over the 8.32-year relationship, respectively, rather than just twice.

(Fun fact: another set of latitude circles whose sizes are an inverse-integer sequence is a lesser-known solution to the famous cheeky bear color problem (the well-known solution is a 1-radian arc around the North Pole), although obtaining the ultimate answer then fails due to the lack of bears in Antarctica)

Some things are better with cheese.

IMDB: Goat Story (2008; user rating 33%, or 39% at ČSFD, see also popular YouTube review)
IMDB: Goat Story 2: with Cheese (2012; user rating 36%, or or 45% at ČSFD, see also popular YouTube review)

No, “goat” does not stand for “greatest of all time” (as you might have guessed) but it’s the name (and species) of the main supporting character. In fact, “goats” (kozy in Czech) means “boobs”, which is where a major part of the first film’s humor comes from and probably why the Shrek donkey ripoff is specifically a goat.

If probability engines* aren’t allowed to offer faster rides by exceeding the speed limit, how are the companies meant to stay competitive and innovate? The state’s whole thing is “move fast and break things”. /s

* and the occasional intervention from an underpaid remote worker in Bangladesh with 720p video at a 100ms ping and the cheapest video game controller

I wonder if random events get skipped every day as a result of him dozing off

There won’t be a date number 2, she will propose on date number 1

wheel spinning

That’s the point, innit?

Or you can do this and find out how squeaky the house frame is!